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Configuration = 33
cycles = (10 4 1 7 2)(9 6 3 8 5)

a = 4, b = 7, c = 10
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cycles = (10 2)(9 3 5 8 6)(7)(4 1)

a = 3, b = 5, c = 9
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cycles = (10 2)(9 6 4)(8 1)(7)(5)(3)

a = 2, b = 8, c = 10
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cycles = (10 1 2)(9)(8 6 3)(7)(5)(4)

a = 1, b = 2, c = 10
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cycles = (10)(9)(8)(7 5 2)(6)(4)(3)(1)